Lowest Common Multiples by Boxed Rockets

Find the LCM as a product of prime numbers

Question 1:

$A = 2^{5} \times 5 B = 2^{2} \times 3^{2} \times 5$

$LCM = 2^{5} \times 3^{2} \times 5$

Question 2:

$A = 2^{2} \times 3^{3} B = 2^{2} \times 3 \times 5$

$LCM = 2^{2} \times 3^{3} \times 5$

Question 3:

$A = 2^{2} \times 3^{2} \times 5 B = 3 \times 5^{2}$

$LCM = 2^{2} \times 3^{2} \times 5^{2}$

Question 4:

$A = 3^{2} \times 5 B = 2 \times 3 \times 5$

$LCM = 2 \times 3^{2} \times 5$